Quis 1 Aljabar Linear

1.A (-5,7) dengan gradient 4

      Jawab : y – y1 = m(x - x1)

                     Y – 7 – 4 (x –(-5)

                       Y = 4x – 27

      B. a = (-3,10) dan b(2,-3)

                Y – y1   =   x – x1

               Y2 – y1    x2 –x1

                Y – 10   =   x – ( -3 )

                -3 – 10       2 – (-3)

                Y  +  10     =   x + 3

                -3 – 10           2 + 3

                Y + 10       =   x + 3

                 -13                 5

                5(y + 10)    =  -13 (x -13

                5y + 50     =    13x – 39

                5y    = -13x  -  39 -50

                5y  =  -13x -  89

2. A .      3x = 2y – 10

                X = 5y

                3 x 5y – 2y = 10

                15x – 2y = 10

                13x = 10

     B.       3y – 3x = 4

                X = 9

                3 (6x) – 3x -4

                18x + 3x =4

15x = 4

                  Y

                                27------------------------.-

                                20                          

                                13

                                12

10

                                8

6    ---------------------------------------------------------------

                                   5    -------------------------------------------------------------

   1 -----------------------------------------------------------------------------                     X

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